B\u01b0\u1edbc 2: B\u1eaft \u0111\u1ea7u xu\u1ed1ng ti\u1ec1n<\/strong><\/h3>\n\n\n\nSau \u0111\u00f3, nh\u00e0 c\u00e1i s\u1ebd l\u1ea5y 4 qu\u00e2n v\u1ecb v\u00e0 b\u1ecf v\u00e0o b\u00e1t \u0111\u1ec3 ti\u1ebfn h\u00e0nh x\u00f3c \u0111\u1ec1u l\u00ean. H\u1ecd ph\u1ea3i \u201c\u0111\u1ea3o\u201d li\u00ean t\u1ee5c nh\u1eb1m \u0111\u1ea3m b\u1ea3o t\u00ednh c\u00f4ng b\u1eb1ng v\u00e0 ng\u1eabu nhi\u00ean 100%.\u00a0<\/p>\n\n\n\n